(x^2-2x+4)=0

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Solution for (x^2-2x+4)=0 equation:


Simplifying
(x2 + -2x + 4) = 0

Reorder the terms:
(4 + -2x + x2) = 0

Remove parenthesis around (4 + -2x + x2)
4 + -2x + x2 = 0

Solving
4 + -2x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-4' to each side of the equation.
4 + -2x + -4 + x2 = 0 + -4

Reorder the terms:
4 + -4 + -2x + x2 = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -2x + x2 = 0 + -4
-2x + x2 = 0 + -4

Combine like terms: 0 + -4 = -4
-2x + x2 = -4

The x term is -2x.  Take half its coefficient (-1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
-2x + 1 + x2 = -4 + 1

Reorder the terms:
1 + -2x + x2 = -4 + 1

Combine like terms: -4 + 1 = -3
1 + -2x + x2 = -3

Factor a perfect square on the left side:
(x + -1)(x + -1) = -3

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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